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Quadrilateral ABCD is rotated 90 degrees CCW about the origin THEN reflected across the x - axis.
What will be coordinate of C''? (no spaces in answer, use parentheses)

FIRST PERSON TO ANSWER BRAINLIEST Quadrilateral ABCD is rotated 90 degrees CCW about the origin THEN reflected across the x axis What will be coordinate of C no class=

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Answer:   (-6, -5)

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Explanation:

CCW = counter-clockwise

The rule for a 90 degree CCW rotation is this

[tex](\text{x}, \text{y})\to(-\text{y}, \text{x})[/tex]

it only works if the center of rotation is the origin.

The x and y coordinates swap places. Then you change the sign of the first coordinate after the swap occurred.

Applying that rotation rule to point C(5, 6) gets us to C ' (-6, 5).

Then to reflect over the x axis, we flip the sign of the y coordinate. The x coordinate stays the same. The notation would be [tex](\text{x}, \text{y})\to(\text{x}, -\text{y})[/tex]

So we go from C ' (-6, 5) to C '' (-6, -5)

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