Answer:
-24.2487113m/s
Explanation:
vi=0, x=30, a=9.8, t=?, vf=?
x=vi*t+.5*a*t^2
30=.5*9.8*t^2
30=4.9*t^2
t=2.4743583s
vf=vi+a*t
vf=0+9.8*2.4743583
vf=24.2487113m/s
Then change it to negative because you are going down.
Answer:
Below
Explanation:
Here are all the values that we are given :
Initial velocity Vi = 0 m/s
Vertical distance Dy = 30 m
All objects accelerate towards earth at a rate of 9.8 m/s^2, this is our acceleration
We can use this formula to find the rocks final velocity as it hits the water :
finalvelocity^2 = initialvelocity^2 + 2(acceleration)(distance)
Plug in our values :
Vf^2 = 0^2 + 2(9.8m/s^2)(30m)
Vf^2 = 588
Square this number to get Vf
Vf = 24.2487 m/s
Now we have to round this number to significant figures. In this case we have to round it to 1 sig fig as the the only number we are given, 30, has 1 sig fig :
Vf = 20 m/s
Hope this helps! Best of luck <3
