Answer:
a) T = 1.405 s
b) Period not depends on the amplitude
c) T = 1.987 s
d) T = 0.811 s
e) The period will change by a small value
The rank are:
Tc > Ta = Tb > Te > Td
Explanation:
Given:
m = mass = 0.3 kg
A = amplitude = 0.4 m
k = force constant = 6 N/m
a) The time period is:
[tex]T = 2\pi \sqrt{\frac{m}{k} } =2\pi \sqrt{\frac{0.3}{6} } =1.405 s[/tex]
b) Period not depends on the amplitude
c) Same as a):
[tex]T = 2\pi \sqrt{\frac{m}{k} } =2\pi \sqrt{\frac{0.6}{6} } =1.987 s[/tex]
d) Same as a):
[tex]T = 2\pi \sqrt{\frac{m}{k} } =2\pi \sqrt{\frac{0.3}{18} } =0.811 s[/tex]
e) if a small resistive force is added the period will change by a small amount. The rank are:
Tc > Ta = Tb > Te > Td
