Respuesta :
Answer:
x ≤ 6 and x ≥ 2
Step-by-step explanation:
For now, we will start with doing each problem at a time. Here is your equation:
2x - 4 ≤ 8
First, you want to get the variable by itself. So, you add 4 to both sides. It will look like this:
2x - 4 ≤ 8
+ 4 + 4
The four being added on the left side cancels out, and you add 4 to 8. Now, it should look like this:
2x ≤ 12
Next, you want the x by itself. So, you would divide both sides by 2.
2x ≤ 12
/2 /2
2 divided by 2 cancels out, and 12 divided by 2 equals 6. Now, you have a final answer of:
x ≤ 6
But, you now have to do the other one!
Here is what you start off with:
x + 5 ≥ 7
First, you want the variable side by itself. So, you subtract 5 from both sides.
x + 5 ≥ 7
- 5 -5
Now, you have this:
x ≥ 2
Because the variable is already by itself, you don't need to do any more division and this is you final answer. Now put both answers you got together which equals:
x ≤ 6 and x ≥ 2
First of all, we have to solve both inequalities: for the first one we have
[tex]2x-4\leq 8[/tex]
Add 4 to both sides
[tex]2x\leq 12[/tex]
Divide both sides by 2:
[tex]x\leq 6[/tex]
For the second one we have
[tex]x+5\geq 7[/tex]
Subtract 5 from both sides
[tex]x\geq 2[/tex]
So, our solution set is composed by all numbers that are less than 6 (included) and more than 2 (included). Using all possible notations, we have
[tex][2,6],\quad 2\leq x \leq 6,\quad \{x \in \mathbb{R}: 2\leq x \leq 6\}[/tex]