Answer:
The length of the train in the frame of the lecture room is 40.59 m.
Explanation:
Given that,
Speed = 0.894 c
Original length = 90.6 m
We need to calculate the length of the train in the frame of the lecture room
Using formula of length contraction
[tex]L=L_{0}\sqrt{1-(\dfrac{v}{c})^2}[/tex]
Where, [tex]L_{0}[/tex]=original length
v = speed of train
Put the value into the formula
[tex]L=90.6\sqrt{1-(\dfrac{0.894c}{c})^2}[/tex]
[tex]L=90.6\sqrt{1-0.894^2}[/tex]
[tex]L=40.59\ m[/tex]
Hence, The length of the train in the frame of the lecture room is 40.59 m.
