Respuesta :
ok so solve each
A. c+14<24
c<10
false since 10 is included in the solution set (and > means not including as well)
B. C+18>24
subtract 18
C>6
false since 5 is in the solution set (and 5<6)
C. C+18>24
subtract 18
C>6
false again since 5 is included
D. C+14<24
subtract 14
C<10
treu since < means c is less than or equal to 10
answer is D
A. c+14<24
c<10
false since 10 is included in the solution set (and > means not including as well)
B. C+18>24
subtract 18
C>6
false since 5 is in the solution set (and 5<6)
C. C+18>24
subtract 18
C>6
false again since 5 is included
D. C+14<24
subtract 14
C<10
treu since < means c is less than or equal to 10
answer is D
Solve each given inequality.
A. C + 14 < 24
C < 10
This doesn't work because the set has 10, which is equal to but not less than 10.
B. [tex]C + 18 \leq 24[/tex]
C[tex]C \leq 6[/tex]
This doesn't work because 9 and 10 are greater than 6.
C. [tex]C + 18\ \textgreater \ 24[/tex]
C > 6
This doesn't work because 5 is less than 6.
D. C + 14 ≤ 24
C ≤ 10
This works because all the numbers in the given set are either less than or equal to 10.
A. C + 14 < 24
C < 10
This doesn't work because the set has 10, which is equal to but not less than 10.
B. [tex]C + 18 \leq 24[/tex]
C[tex]C \leq 6[/tex]
This doesn't work because 9 and 10 are greater than 6.
C. [tex]C + 18\ \textgreater \ 24[/tex]
C > 6
This doesn't work because 5 is less than 6.
D. C + 14 ≤ 24
C ≤ 10
This works because all the numbers in the given set are either less than or equal to 10.