Answer:
Given the equation: [tex]2(x-3)+9=3(x+1)+x[/tex]
Distributive property of multiplication states that when a number is multiplied by the sum of the two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately i.e,
[tex]a \cdot (b+c) = a\cdot b+a\cdot c[/tex]
Now, using distributive property to LHS and RHS, we get
[tex]2x-6+9=3x+3+x[/tex]
Combine like terms on RHS;
[tex]2x-6+9 = 4x+3[/tex]
or
[tex]2x+3 = 4x+3[/tex]
Subtract 3 from both sides of an equation;
2x+3-3 =4x+3-3
Simplify:
2x = 4x
or
[tex]4x-2x =0[/tex]
2x = 0
⇒ x =0
Therefore, the value of x in the given equation
[tex]2(x-3)+9=3(x+1)+x[/tex] is 0.
