The equation of a circle in standard form is
[tex] (x - h)^2 + (y - k)^2 = r^2 [/tex]
where (h, k) is the center of the circle, and r is the radius if the circle.
We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.
M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).
To find the radius, we find the length of the given diameter and divided by 2.
[tex] d = \sqrt{(-6 - 6)^2 + (6 - (-2))^2)} [/tex]
[tex] d = \sqrt{144 + 64} [/tex]
[tex] d = \sqrt{208} [/tex]
[tex] r = \dfrac{d}{2} = \dfrac{\sqrt{208}}{2} = \dfrac{\sqrt{208}}{\sqrt{4}} = \sqrt{52} [/tex]
[tex] (x - 0)^2 + (y - 2)^2 = (\sqrt{52})^2 [/tex]
[tex] x^2 + (y - 2)^2 = 52 [/tex]
