The measure of the length of one side of the painting (in inches) is [tex]36\;\rm{inches}[/tex].
Given:
Area of square-shaped painting is [tex]9\;\rm{ft^2[/tex].
According to the question, the Area of painting is [tex]9\;\rm{ft^2[/tex].
As we know that the area of the square is formulated as,
[tex]\rm{side\times side\;sq. \;units[/tex]
Here, the length of one side of square-shaped painting is calculated as
[tex]\sqrt{9\;\rm{ft^2} }=3\;\rm{ft[/tex]
Now,
[tex]1\;\rm{ft}=12\;inches\\3\;\rm{ft}=3\times12\;inches\\3\;\rm{ft}=36\;inches[/tex]
Therefore, the length of one side of the painting (in inches) is [tex]36\;\rm{inches[/tex].
Learn more about the Area of the square:
here:https://brainly.com/question/11505374
