we know that
the equation of a circle is
(x-h+(y-k)²=r²
where (k,k)----> is the center
and
r----> is the radius
y²+2x+x²-24y= -120
Group
terms that contain the same variable
(y²-24y)+(x²+2x)=-120
Complete
the square twice. Remember to balance the equation by adding the same constants
to each side
(y²-24y+144)+(x²+2x+1)=-120+144+1
Rewrite as perfect squares
(y-12)²+(x+1)²=25
(x+1)²+(y-12)²=5²
the answer isthe coordinates of the center are (-1,12)the radius is 5 units
