Well, the " kg-m/s² " is a Newton ... that's a [force].
When it's multiplied by another 'm', you get " kg-m²/s² ".
That's [force] · [distance], which is [work] or [energy].
So far, we have [energy] / C .
If the 'C' stands for 'Coulomb' of charge, then the whole thing
is [energy] / [charge] or " joule / Coulomb ". That's a volt !
So the whole thing is a unit of electrical potential, potential difference,
or electromotive force.
When I first saw this question, I was trying hard to make it a unit
of something that has to do with heat, because I thought that big
' C ' out at the end was actually ' °C ' for Celsius degree. But I think
the electrical stuff is better. So that's my answer and I'm stickin' to it.
