[tex]\sqrt{64}[/tex] is a rational number, therefore option C is correct
What is a rational number?
It is the any real number which can be represented by [tex]\frac{p}{q}[/tex] form, where p and q are integers and q[tex]\neq[/tex]0.
In other words, radical is rational number if it is a perfect square root value which can be represented as [tex]\frac{p}{q}[/tex] form otherwise it is an irrational real number. Here radical is nothing but the under root term.
Given that
[tex]\sqrt{20}[/tex] and [tex]\sqrt{83}[/tex] radical values are not perfect square roots, therefore these are irrational numbers.
In the same way, the [tex]\pi[/tex] is also not a rational number because it can't be represented as a simple [tex]\frac{p}{q}[/tex] form. We write it as 22/7 but it is not completed, as its a infinite decimal value i.e., 3.14285...
Hence option C is a rational number.
∵[tex]\sqrt{64}[/tex] = 8, is a perfect square root which can be represented as [tex]\frac{8}{1}[/tex] i.e., [tex]\frac{p}{q}[/tex] form, where p and q are integers and q[tex]\neq[/tex]0.
To know more about rational numbers, refer to the link
https://brainly.com/question/17450097
#SPJ2
