Ninety-three percent of a town’s population own cars. If the number of cars owned is 5,208, what is the population of the town, if nobody owns more than 1 car?

PLEASE HELP, I DON'T GET THIS!! :((

Respuesta :

What the problem is saying is that 93% of the town's population is 5,208. If no one owns more than one car, then each car in the town accounts for one person. So, therefore, 93% of the town = 5,208.

The total population of the town can be found by setting up a proportion.

[tex] \frac{5208}{93} = \frac{x}{100} [/tex]

Cross-multiply: [tex]520800=93x[/tex]

Solve for x, the town's population: [tex]x=5600[/tex]

There are 5,600 people in the town.
Hey there :)

93% of a town's population own cars
If number of cars owned is 5,208

Population of town is?
Let p represent population of town

[tex] \frac{93}{100} [/tex] of p = 5208
[tex] \frac{93}{100} [/tex] × p = 5208

Divide 5208 by p in order to do cross multiplication ( easier way )
[tex] \frac{93}{100}= \frac{5208}{p} [/tex]

Cross multiply:

93p = 5208 × 100
93p = 520800

Divide by 93 in order to find value of p
[tex] \frac{93p}{93} = \frac{520800}{93} [/tex]
p = 5600

The total population of the town is 5600