The equation 2y=5 is not correct; it is neither logarithmic nor exponential. Fix this by denoting exponentiation with the symbol "^": the equation 2^y=5
You haven't shared the graphs mentioned in your problem statement. However, this 2^y = 5 can be solved for y, as follows:
ln is the natural log operator.
ln 2^y = ln 5, or y(ln 2) = ln 5. Solving for y, y = (ln 5) / (ln 2). You could evaluate these logs on a calculator. If you had the correct graph in front of you, you could draw a horiz. line thru y = 5 and estimate the value of the x-coordinate of the point where the expo. graph and the line y=5 intersect.
