Respuesta :
The vector u is <9, 12> which means "start at any point, go to the right 9 units, and then up 12 units". If the starting point is point P = (0,0), then the terminal point is in quadrant I. For vector cu, the terminal point is now in quadrant III because we multiply the coordinates of (9,12) by some negative number c (eg: c = -1 so the terminal point is (-9,-12))
Answer: Choice B) terminal point of vector cu is in quadrant 3
Answer: Choice B) terminal point of vector cu is in quadrant 3
The terminal point of a vector is its final point.
The statement that describes cu is: (B) the terminal point of vector cu lies in quadrant III
The given parameters are:
[tex]\mathbf{P = (0,0)}[/tex]
[tex]\mathbf{Q = (9,12)}[/tex]
[tex]\mathbf{c < 0}[/tex]
[tex]\mathbf{c < 0}[/tex] means that: we multiply by a negative number.
So, we have:
[tex]\mathbf{P' = (-0,-0)}[/tex]
[tex]\mathbf{P' = (0,0)}[/tex]
[tex]\mathbf{Q' = (-9,-12)}[/tex]
The coordinates of Q' imply that, the x and y coordinates are negative values.
The third quadrant have its x and y values to be negative.
Hence, the terminal point of cu lies in the third quadrant.
Read more about terminal points at:
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