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Almost a billion people on the planet don't have access to clean drinking water." if there were 7.2×109 people in the world in 2014, then approximately what percent of them lived without clean drinking water? round to the nearest tenth of a percent.

Respuesta :

13.9%.

7.2 x 10^9 = 7,200,000,000.

Since 1 billion = 1,000,000,000 out of these 7,200,000,000 do not have access to clean water, we find the percent by taking:
1,000,000,000/7,200,000,000 = 10/72 = 13.9%
JeanaShupp

Answer: 13.9%

Step-by-step explanation:

Given : Almost a billion people on the planet don't have access to clean drinking water."

We know that 1 billion = [tex]1,000,000,000=10^9[/tex]

There were [tex]7.2\times10^9[/tex] people in the world in 2014.

Now, the percent of people lived without clean drinking water :-

[tex]\dfrac{\text{Number of people lived without clean water}}{\text{Total people in the world}}\times100\\\\=\dfrac{10^9}{7.2\times10^9}\times100\\\\=\dfrac{1}{7.2}\times100\\\\=0.138888888889\times100\\\\=13.8888888889\%\approx13.9\% \ \ \text{[Round to the nearest tenth of a percent]}[/tex]

Hence, approximately 13.9% of them lived without clean drinking water.

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