Respuesta :

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The  molarity  of  aqueous   solution  containing  40.0g  of  glucose  in  1.5 L  of   solution  calculated  as  follows

molarity  = moles/volume  in  liters

find  the  moles  of  glucose  = mass  /molar  mass
=  40/  180.06  =  0.222 moles
 molarity  is  therefore = 0.222/1.5 =  0.148 M

Answer:

Molarity of aqueous solution = 0.14 M

Explanation:

Molarity is defined as the number of moles of solute present in 1 L of the solution.

[tex]M = \frac{W}{M\times \ V\ in\ L}[/tex]

Where,

W = Mass of the solute

M = Molecular mass of the solute

V = Volume of the solution

Volume of the solution = 1.5 L

Mass of glucose = 40.0 g

Molecular mass of glucose = 180.16 g/mol

[tex]M = \frac{40.0}{180.16\times 1.5}[/tex]

           = 0.1480 M

            = 0.14 M

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