For this case we have that the initial and final peach diameters are:
[tex]D_ {i} = 98 \ mm\\D_ {f} = 188,869 \ mm[/tex]
According to the difference percentage we have:
[tex]\frac {188,869-98} {98} = 0.927[/tex]
That is to say, the peach grew by almost 93%. That is, almost twice its diameter.
Answer:
the peach grew by almost 93%. That is, almost twice its diameter.
