Answer:
a = 16 or a = 12
Step-by-step explanation:
Given quadratic equation,
[tex]a^2-28a+192=0[/tex]
Step 1 : Move constant term to the right side,
[tex]a^2-28a=-192[/tex]
Step 2 : Add the square of the half of the coefficient of x on the both sides,
[tex]a^2-28a+196=-192+196[/tex]
[tex]a^2-28a+196=4[/tex]
Step 3 : Plug the terms in the left side into the quadratic formula,
[tex](a-14)^2=4[/tex]
Step 4 : Taking log both sides,
[tex]a-14=\pm 2[/tex]
Step 5 : Isolate the variable,
[tex]a=14\pm 2[/tex]
Hence, the solution of the given equation is,
a = 14 + 2 or a = 14 - 2
a = 16 or a = 12
