PLEASE HELP EASY ALGEBRA What is the sum of the geometric sequence 1, 3, 9, … if there are 10 terms?
A: 29,524
B: 55,987
C: 87,381
D: 88,573

Respuesta :

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Each number in the 10-digit sequence is multiplied by 3

1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683

1*3= 3
3*3=9
9*3=27
27*3=81
81*3=243
243*3=729
729*3=2187
2187*3=6561
6561*3=19683

Total of numbers= 29524

ANSWER: A) 29,524

Hope this helps! :)

The sum of geometric sequence  of 10 terms is 29,524

What is series?

A series in math is simply the sum of the various numbers or elements of the sequence. For example, to make a series from the sequence of the first five positive integers 1, 2, 3, 4, 5 we will simply add them up. Therefore 1 + 2 + 3 + 4 + 5 is a series.

What is geometric sequence?

A geometric sequence is a sequence in which the ratio consecutive terms is constant.

An infinite series of the form a , ar , ar2 , ar3+⋯, where r is known as the common ratio and a is first term .

What is the geometric series?

A  geometric series is the sum of an infinite number of terms that have a constant ratio between successive terms.

An infinite series of the form a + ar + ar2 + ar3+⋯, where r is known as the common ratio and a is first term .

What Is the Geometric Sum Formula of finite terms?

[tex]Sn= \frac{a(r^{n}-1) }{r-1}[/tex]

Where

a is the first term

r is the common ratio

n is the number of terms

[tex]S_{n}[/tex] is sum of all the terms

According to question

1 + 3 + 9 + ................ 10th term

where

a = 1

r = 3/1 or 9/3 = 3 (common ratio )

n= 10

[tex]Sn= \frac{a(r^{n}-1) }{r-1}[/tex]

[tex]S_{10} = \frac{1(3^{10}-1) }{3-1}[/tex]

[tex]S_{10} = \frac{59049-1}{2}[/tex]

[tex]S_{10} = 29,524[/tex]

Hence , sum of geometric sequence of 10 terms  is 29,524

To know more about  geometric sequence here

https://brainly.com/question/13008517

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