Answer:
Diana have the same error percent in both games.
Step-by-step explanation:
We have been given that Diana guesses that their are 120 gum balls in a jar. There are actually 96. In another game she guesses that there are 75 jelly beans in a jar. There are actually 60.
Let us find error percent for each scenario.
[tex]\text{Error percent}=\frac{| \text{Approx-Exact}|}{\text{Exact}}\times 100\%[/tex]
[tex]\text{Error percent in 1st game}=\frac{|120-96|}{96}\times 100\%[/tex]
[tex]\text{Error percent in 1st game}=\frac{|24|}{96}\times 100\%[/tex]
[tex]\text{Error percent in 1st game}=\frac{24}{96}\times 100\%[/tex]
[tex]\text{Error percent in 1st game}=0.25\times 100\%[/tex]
[tex]\text{Error percent in 1st game}=25\%[/tex]
Now, we will find error percent in 2nd game.
[tex]\text{Error percent in 2nd game}=\frac{|75-60|}{60}\times 100\%[/tex]
[tex]\text{Error percent in 2nd game}=\frac{|15|}{60}\times 100\%[/tex]
[tex]\text{Error percent in 2nd game}=\frac{15}{60}\times 100\%[/tex]
[tex]\text{Error percent in 2nd game}=0.25\times 100\%[/tex]
[tex]\text{Error percent in 2nd game}=25\%[/tex]
Since error percent of both games in 25%, therefore, Diana have the same error percent in both games.
