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Can someone please explain to me how to do this!? What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?

Respuesta :

PV=nRT
(.98)V=(.485moles)(.0821)296
solve for V

p is for pressure (.98 atm)
you are solving for the volume V
n is moles (.485)
the R value is a constant which is .0821 when your pressure is in atm
T is temperature in Kelvin so add 273 to your celsius temp to get 296

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