Respuesta :
Remember that the general decay equation is:
[tex]y=A(1-r)^{x}[/tex]
where
[tex]y[/tex] is the amount after a time [tex]x[/tex]
[tex]A [/tex] is the initial amount
[tex]r[/tex] is the the decay percent in decimal form
The first ting we are going to do is find [tex]r[/tex] by dividing our decay rate of 25% by 100%: [tex]r= \frac{25}{100} =0.25[/tex].
We also know from our problem that [tex]y=64[/tex]. Lets replace [tex]y[/tex] and [tex]r[/tex] in our formula:
[tex]64=A(1-0.25)^{x} [/tex]
[tex]64=A(0.75)^{x} [/tex]
We know now that our decay rate is 0.75, and since 0.75<1, we can conclude that this situation represents exponential decay.
Now, to find the initial amount, we are going to solve our equation for [tex]A[/tex]:
[tex]64=A(0.75)^{x} [/tex]
[tex]A= \frac{64}{0.75 ^{x} } [/tex]
Notice that [tex]A[/tex] will depend on the number of ours [tex]x[/tex].
[tex]y=A(1-r)^{x}[/tex]
where
[tex]y[/tex] is the amount after a time [tex]x[/tex]
[tex]A [/tex] is the initial amount
[tex]r[/tex] is the the decay percent in decimal form
The first ting we are going to do is find [tex]r[/tex] by dividing our decay rate of 25% by 100%: [tex]r= \frac{25}{100} =0.25[/tex].
We also know from our problem that [tex]y=64[/tex]. Lets replace [tex]y[/tex] and [tex]r[/tex] in our formula:
[tex]64=A(1-0.25)^{x} [/tex]
[tex]64=A(0.75)^{x} [/tex]
We know now that our decay rate is 0.75, and since 0.75<1, we can conclude that this situation represents exponential decay.
Now, to find the initial amount, we are going to solve our equation for [tex]A[/tex]:
[tex]64=A(0.75)^{x} [/tex]
[tex]A= \frac{64}{0.75 ^{x} } [/tex]
Notice that [tex]A[/tex] will depend on the number of ours [tex]x[/tex].
Answer:
This situation models exponential decay because the substance decays with time.
The radioactive substance decays at the rate of : 25%
r=25/100 =0.25
The initial amount of substance is 64 grams. So, . A=64
Step-by-step explanation: