What are the roots of the equation?
x^2+24=−11x
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Answer:
[tex]x_1 = -8[/tex]
[tex]x_2 = -3[/tex]
Step-by-step explanation:
Given the equation:
[tex]x^2+24 = -11x[/tex]
Add 11x to both sides we have;
[tex]x^2+11x+24 = 0[/tex]
Split the middle terms we have;
⇒[tex]x^2+8x+3x+24 = 0[/tex]
⇒[tex]x(x+8)+3(x+8)= 0[/tex]
⇒[tex](x+8)(x+3)= 0[/tex]
By zero product property we have;
x+8 = 0 and x+3= 0
⇒x = -8 and x = -3
Therefore, the roots of the given equations are:
[tex]x_1 = -8[/tex]
[tex]x_2 = -3[/tex]