Respuesta :
Nothing to drag; nowhere to drag it to.
Park A's population can be modeled by
.. y = 150*1.2^x
Park B's population can be modeled by
.. y = 150*0.8^x
Park A's population can be modeled by
.. y = 150*1.2^x
Park B's population can be modeled by
.. y = 150*0.8^x
Answer:
Step-by-step explanation:
Initial population of bears =150
Park A is given that the population increases by 20% each year
This gives that in year x population would be
P(t) = [tex]150(1+\frac{20}{100} )^x\\=150(1.2)^x[/tex]
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In the II park park B, the population decreases by 20%
Hence have population at time x as
P(x) = [tex]150(1-\frac{20}{100} )^x\\=150(0.8)^x[/tex]