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What mass of electrons would be required to just neutralize the charge of 5.0 g of protons? (the mass of a proton is 1.67262×10−24g, and the mass of an electron is 9.1×10−28g.)?

Respuesta :

pate02
To  neutralize the charge of 1.0g of electrons?

Answer:

[tex]m = 2.72 \times 10^{-3} g[/tex]

Explanation:

total number of protons in 5 gram of total mass is given as

[tex]N = \frac{m}{m_p}[/tex]

here we have

[tex]N = \frac{5}{1.67262 \times 10^{-24}}[/tex]

[tex]N = 2.99 \times 10^{24}[/tex]

now to neutralize the charge we require same amount of negatively charge electrons

so we have

[tex]m = N(m_e)[/tex]

[tex]m = (2.99 \times 10^{24})(9.1 \times 10^{-28})[/tex]

[tex]m = 2.72 \times 10^{-3} g[/tex]