A car with a mass of 525kg is being pushed west (left) by a force of 375n from its engine. the coefficient of friction felt by the car is .0420.
a.calculate the force weight of the car.
b.calculate the force friction acting on the car.
c.what is the net force acting on this car?
d.calculate the acceleration of the car.

Respuesta :

Explanation:

It is given that,

Mass of the car, m = 525 kg

Applied force, F = 375 N

The coefficient of friction felt by the car is 0.42, [tex]\mu=0.42[/tex]

(a) The weight of the car is given by :

[tex]W=mg[/tex]

[tex]W=525\times 9.8[/tex]

W = 5145 N

(b) The force of friction acts in the opposite direction of motion. It can be calculated as :

[tex]f=\mu mg[/tex]

[tex]f=0.42\times 5145[/tex]

f = 2160.9 N

(c) Here, the force of friction is greater than the applied force. As a result, the ball will not moves. So, the net force acting on this car is 0.

(d) As the net force acting on the car is 0. There will be no acceleration in the car.