A line passes through (–7, –5) and (–5, 4).Write an equation for the line in point-slope form.
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Slope m = diffy/diffx
m = 9/2
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y - y1 = m*(x - x1) where (x1,y1) is either point.
Rewrite into any form.
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Or,
| x y 1|
|-7 -5 1| = 0
|-5 4 1|
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x*(-5-4) - y*(-7+5) + (-28-25) = 0
-9x + 2y - 53 = 0
2:
Answer:
The equation of the line in slope-intercept form is y = 92x + 532.
The equation of the line in standard form is 9x−2y=−53
Explanation:
The
slope of the line passing through (−7,−5)and(−5,4) is m=y2−y1x2−x1=4+5−5+7=92
Let
the equation of the line in slope-intercept form be y=mx +cory =92x+c The
point (-7,-5) will satisfy the equation . So, −5=92⋅ (−7)+corc=632−5=532
Hence
the equation of the line in slope-intercept form is y=92x+532.
The
equation of the line in standard form is
y=92x+532.or2y=9x+53
or
9x−2y =−53
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