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Josefina tosses a ball upward with an initial velocity of 76 feet per second. She tosses it from an initial height of 2 feet. Find the approximate time that the ball hits the ground. Use the function h(t) = -16t2 + 76t + 2

Respuesta :

It takes approximately 4.8 seconds.

Using the equation h(t)=-16t²+76t+2 and the quadratic formula we have:

[tex]t=\frac{-76\pm \sqrt{76^2-4(-16)(2)}}{2(-16)} \\ \\=\frac{-76\pm \sqrt{5776--128}}{-32} \\ \\=\frac{-76\pm \sqrt{5776+128}}{-32} \\ \\=\frac{-76\pm \sqrt{5904}}{-32} \\ \\=\frac{-76\pm 76.8}{-32}=\frac{-76+76.8}{-32}\text{ or } \frac{-76-76.8}{-32} \\ \\=\frac{0.8}{-32}\text{ or } \frac{-152.8}{-32}=-0.025\text{ or } 4.775[/tex]

The second value would be when it hits the ground again.

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