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The sum of the three Romano brothers is 63. If there ages can be represented as consecutive integers, what is the age of the middle brother.

Respuesta :

mathstudent55
Let the age of the middle bother be x.
The oldest brother is 1 year older than the middle brother,so his age is x + 1.
The youngest brother is 1 year younger than the middle bother, so his age
is x - 1.

Add the three ages and get 63.
x - 1 + x + x + 1 = 63

3x = 63

x = 21

Answer: The age of the middle brother is 21.

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