Respuesta :
The number 0.8 represents that every foot of pipe removes 20% of the pollulant, leaving the 80% ( 80/100=0.80)
Answer: Every foot of the pipe keeps 80% of the pollutant.
Justification:
1) the function is f(x) = 10 * (0.8)^x
2) That means that the amount of fuel, f(x), is multiplied by 0.8 every foot it passes.
Initially the amount of poluulants 10 tons.
After 1 foot the amount pollulants remaining is 10 * 0.8 = 8 tons
That is (8/10)*100% = 80%.
3) You can to that same calculation in a general form to jusitfiy the result for every foot.
Suppose x = n
=> f(n) = 10 * (0.8)^n
=> x + 1 = n+1 => f(n+1) = 10 * (0.8)^(n+1)
Percent of pollulant remaining, % = [ f(n+1) / f(n)] * 100
=> % = { [10 * 0.8^(n+1) ] / [10 * 0.8^(n) ] } * 100 = 0.8^ (n+1-n) * 100 = 0.8^(1) * 100 = 0.8 * 100 = 80.
So, 80% of pollulant remains after every foot o fpipe.
Justification:
1) the function is f(x) = 10 * (0.8)^x
2) That means that the amount of fuel, f(x), is multiplied by 0.8 every foot it passes.
Initially the amount of poluulants 10 tons.
After 1 foot the amount pollulants remaining is 10 * 0.8 = 8 tons
That is (8/10)*100% = 80%.
3) You can to that same calculation in a general form to jusitfiy the result for every foot.
Suppose x = n
=> f(n) = 10 * (0.8)^n
=> x + 1 = n+1 => f(n+1) = 10 * (0.8)^(n+1)
Percent of pollulant remaining, % = [ f(n+1) / f(n)] * 100
=> % = { [10 * 0.8^(n+1) ] / [10 * 0.8^(n) ] } * 100 = 0.8^ (n+1-n) * 100 = 0.8^(1) * 100 = 0.8 * 100 = 80.
So, 80% of pollulant remains after every foot o fpipe.