A man stands still on a moving walkway that is going at a speed of 0.3 m/s to the south. What is the velocity of the man according to a stationary observer?

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orlandojr4 orlandojr4 · Answer 1 · 2018-02-18T18:08:55+01:00

The velocity is 0.3 m/s South.

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aristocles aristocles · Answer 2 · 2019-05-17T02:34:03+02:00

Answer:

With respect to stationary observer the velocity of man is 0.3 m/s towards South

Explanation:

As we know that here man is standing still on the moving walkway

so here we can say that velocity of man with respect to walkway is zero

[tex]\vec v_{mw} = 0[/tex]

now as per relative velocity concept we know

[tex]\vec v_{mw} = \vec v_m - \vec v_w[/tex]

here we know

[tex]\vec v_m[/tex] = velocity of man with respect to stationary observer

[tex]\vec v_w[/tex] = velocity of walkway

now from above equation we have

[tex]\vec v_m = \vec v_{mw} + \vec v_w[/tex]

now plug in all values in it

[tex]\vec v_m = 0 + 0.3 m/s = 0.3 m/s[/tex] towards South