Respuesta :

tr847007
We are starting with a 12.5 M HCl solution. We want 2.0 L of a 1.0 M HCl solution.

We can start with the solution we want to make and work backwards to determine how much of the 12.5 M solution is required.

2.0L x 1.0 mol/L = 2.0 moles HCl

To make 2 L of a 1.0M solution of HCl, we need 2.0 moles of HCl that we get from the stock solution.

2.0 moles HCl / 12.5 mol/L = 0.16 L = 160 mL of solution.

Therefore, we need 160 mL of the 12.5 M solution of HCl to make 2 L of a 1.0M HCl solution.

Answer: We require 0.16 L of HCl stock solution to make a 2 L of 1 molar HCl solution.

Explanation:

To form a solution of 1M HCl solution from a stock solution of hydrochloric acid, we use the formula:

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the stock solution.

[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of the given HCl solution.

We are given:

[tex]M_1=12.5M\\V_1=?L\\M_2=1M\\V_2=2L[/tex]

Putting values in above equation, we get:

[tex]12.5\times V_1=1\times 2\\\\V_1=0.16L[/tex]

Hence, we require 0.16 L of HCl stock solution to make a 2 L of 1 molar HCl solution.

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