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The question states that we have two separate methyl groups coming off of the main chain. Therefore, if we remove two carbons from the formula C₆H₁₄O, we are left with 4 carbons, suggesting our structure has a 4-carbon main chain, simplified below:

CH₃-CH₂-CH₂-CH₃

We are also told that we have a tertiary alcohol. A tertiary alcohol is when the functional group -OH is attached to a tertiary carbon, which is a carbon containing 3 C-C single bonds. We cannot add the -OH to either end of our 4-carbon chain because the only way to make it a tertiary alcohol would be to add both methyl groups to that same carbon, which would not make them two separate methyl groups. Therefore, the -OH must go on the 2- or 3- carbon in our 4-carbon chain:

CH₃-CH-CH₂-CH₃
         |
        OH

Now that we have our 4-carbon chain with an -OH on the second carbon, the -OH at this time would only be a secondary alcohol since that carbon only has two C-C single bonds. Therefore, we must add another methyl group to that carbon containing the -OH, and this will make it a tertiary alcohol:
        CH₃
         |
CH₃-C-CH₂-CH₃
         |
        OH

We now have 5 carbons in our structure that has a 4-carbon chain with a tertiary alcohol. We added one methyl group to our 4-carbon chain, and must add another methyl group. However, if we add the methyl group to the 1- or 4- carbons at the end of the chain, we will simply extend the chain, but that is not what we want. We need another separate methyl group extending from the original 4-carbon chain. The only place we can put this methyl group is on the 3-carbon. Therefore, the structure we are looking for is:
       CH₃
        |
CH₃-C--CH-CH₃
        |     |
       OH CH₃
ardni313

The name of the alcohol of the molecular formula C₆H₁₄O is

2,3 dimethyl 2 butanol

Further explanation

Alcohol is a carbon compound derived from alkanes with a general formula

[tex]\large{\boxed{\boxed{\bold{C_nH_{2n+2}O}}}[/tex]

Alcohol has a -OH functional group

Based on the location of the bound -OH functional group, alcohol can be divided into three types namely:

  • 1. primary alcohol, the -OH group is attached to a primary C atom (carbon atom which is bound directly to one C atom at another)
  • 2. secondary alcohol, the -OH group is bound to the secondary C atom (carbon atom which is bound directly to the other two C atoms)
  • 3. tertiary alcohol, the -OH group is bound to a tertiary C atom (a carbon atom that is bound directly to three other C atoms)

For tertiary alcohol is denoted by notation 3°

In the statement about the problem there is alcohol with a molecular formula:

[tex]\large{\boxed{\bold{C_6H_{14}O}}}[/tex]

Because there are 2 methyl (CH₃) branches attached to the main chain, the main chain only has 4 C atoms, so the main chain in alcohol is called butanol

C-C-C-C

The methyl branch will be located on C atoms No. 2 and 3 of the main chain because when placed at the end it will form a new main chain that has more than 4 C atoms.

C-C-C-C

    |   |

CH₃ C H₃

The -OH function group we put on a tertiary C atom that is C atom no 2 or 3 (from the same left or right because both C atoms are tertiary)

 OH

    |

C-C-C-C

    |   |

CH₃ C H₃

So the name of the alcohol is (the -OH functional group gets a smaller number)

2,3 dimethyl 2 butanol

Learn more

6-decene is not possible

https://brainly.com/question/2095052

the correct name of the compound

https://brainly.com/question/9535482

'cis' and trans'

https://brainly.com/question/5644969

Keywords: butanol, alcohol, C tertiary

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