Percentage of the compound,
silicon = 6.360 %
bromine = 36.18 %
iodine = 57.46 %
In 100 grams of compound we will have
silicon = 6.36, bromine = 36.18, iodine = 57.46
Molar mass
silicon = 28.09, bromine = 79.90, iodine = 126.09
Calculating the moles,
silicon = 6.36 / 28.09 = 0.226
bromine = 36.18 / 79.90 = 0.452
iodine = 57.46 / 126.09 = 0.455
Divide with the lowest
silicon = 0.226 / 0.226 = 1
bromine = 0.452 / 0.226 = 2
iodine = 0.455 / 0.226 = 2
So the empirical formula would be SiBr2I2