Respuesta :

First solve for B in VB = 2x-11 

BV = 2x - 11
BV / V = 2x - 11 / V
B = 2x - 11 / V

Now solve for A in AB = x + 5
AB = x + 5
AB / B = x + 5 / B
A = x + 5 / B

Now times A and B
[tex]\frac{x + 5}{B} * \frac{2x - 11}{V}[/tex]
Now multiply 
[tex]\frac{x + 5}{B} * \frac{2x - 11}{V}[/tex]
(x + 5)(2x - 11)
[tex]2x^2 - 11x + 10x -55[/tex]
[tex]2x^2 - 1x -55[/tex]
V * B = VB
So our answer is below
[tex]\frac{2x^2 - 1x -55}{VB}[/tex]



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