Draw a line from home plate to second base. The square will be divided into two congruent right triangles.
Focusing on one of the right triangles, we have two legs of 90 feet each and an unknown hypotenuse. Call the hypotenuse x for now
a = 90
b = 90
c = x
Pythagorean theorem
a^2+b^2 = c^2
90^2+90^2 = x^2
8100+8100 = x^2
16200 = x^2
x^2 = 16200
x = sqrt(16200)
x = 127.279
The last value is approximate
So the distance from home plate to second base is approximately 127.279 feet
