Respuesta :
In the compound nh3, nitrogen has an oxidation number of 3+ and hydrogen has an oxidation number of -1
The molecule NH3 have a neutral charge so the number of oxidation number of it's component must be equal to zero. The molecule NH composed of 1 nitrogen and 3 hydrogens. If the nitrogen oxidation number is 3+, then hydrogen would be:
1* N + 3*H=0
1*+3 +3*H=0
3H= -3
H= -1
The molecule NH3 have a neutral charge so the number of oxidation number of it's component must be equal to zero. The molecule NH composed of 1 nitrogen and 3 hydrogens. If the nitrogen oxidation number is 3+, then hydrogen would be:
1* N + 3*H=0
1*+3 +3*H=0
3H= -3
H= -1
Explanation:
Since nitrogen is more electronegative than hydrogen therefore, it attracts the electron of hydrogen atom towards itself. Hence, the hydrogen atom acquires a negative charge in a molecule of ammonia [tex](NH_{3})[/tex].
So, let the oxidation number of hydrogen in [tex]NH_{3}[/tex] is x.
Therefore, calculate the oxidation number of hydrogen as follows.
Oxidation number of nitrogen + [tex]3 \times oxidation number of hydrogen[/tex] = charge on the molecule
3 + 3x = 0
x = [tex]\frac{-3}{3}[/tex]
= -1
Thus, we can conclude that in the compound [tex]NH_{3}[/tex], nitrogen has an oxidation number of 3+ and hydrogen has an oxidation number of -1.
