Answer: The correct answer is 4, 2.
Explanation:
Hybridization is calculated by using the formula:
[tex]\text{Number of electron pairs} =\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
It is given that the hybridization of a molecule is [tex]sp^3d^2[/tex], this means that the number of electron pairs are 6. The molecular geometry of the molecule having electron pairs as 6 is octahederal.
If the molecular geometry of the molecule is square pyramidal, then it would acquire 4 electron pairs as the bonding groups and the rest pairs would be considered as lone pairs.
Hence, the correct answer is 4, 2.
