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Consider a force of 750 n (roughly the weight of an adult human). over what area (in cm2) would this force need to be applied in order achieve a solid pressure (stress) of 25 mpa (the pressure required to rupture average human skin)? [recall : 1 mpa = 106 pa , and 1 pa = 1 n/m2]

Respuesta :

christopher119p0alm8
[tex]p = \frac{f}{a} [/tex]
P=25x10^6 andF=750.So plug in everything to solve for A. which is 3x10^-5m^2 OR 0.3mm^2
Lanuel

The area (in [tex]cm^2[/tex]) this force would need to be applied is 2900 centimeter square.

Given the following data:

  • Force = 750 Newton
  • Pressure = 25 mPa

Conversion:

25 mPa = [tex]25 \times 106[/tex] = 2650 Pa

To find the area (in [tex]cm^2[/tex]) this force would need to be applied:

Mathematically, the pressure acting on area is given by the formula:

[tex]Pressure = \frac{Force}{Area}[/tex]

Making area the subject of formula, we have:

[tex]Area = \frac{Force}{Pressure}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Area = \frac{750}{2560}[/tex]

Area = 0.29 [tex]m^2[/tex]

To centimeter squared:

1 meter square = 10,000 centimeter square

0.29 meter square = X centimeter square

Cross-multiplying, we have:

[tex]X = 0.29 \times 10000[/tex]

X = 2900 centimeter square

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