A rabbit population doubles every 4 weeks. There will be 56 rabbits in 98 days.
Given :
A rabbit population doubles every 4 weeks.
The doubling formula for population is
[tex]P(t)=P(2)^\frac{t}{d}[/tex]
where P is the initial population
t is the time taken to increase
d is the doubling time
Rabbit population doubles every 4 weeks that is 28 days . So , d=28
We need to find how many rabbits are there in 98 days
the value of t=98 days
initial population is 5 rabbits
Replace all the values
[tex]P(t)=P(2)^\frac{t}{d}\\P(28)=5(2)^\frac{98}{28}\\P(28)=5 \cdot 2^3\cdot 2^{\frac{1}{2}}\\P(28)=56.56854[/tex]
There be 56 rabbits in 98 days
Learn more : brainly.com/question/3302970
