Solution: A triangle ABC having vertices at A(1, 2) , B(1, 6) , and C(5, 6).
AB= 4 units
BC= 4 units
CA = [tex]\sqrt{(5-1)^{2} +(6-2)^{2} }=\sqrt{32}=4\sqrt{2}[/tex]
The triangle ABC is right angled triangle.
And Orthocentre of a triangle is the point where perpendiculars of triangle meet.As two perpendiculars AB and AC meet at Point B , So Point B(1,6) is orthocenter of triangle.
