f(x)=|x+3|-5 is the transformed function.
Take 3 values of x, -4, -3, -2 original f(x) for these are 1, 0, 1.
The same values for the transformed function are -4, -5, -4.
If we try to bring the -5 into the modulus, we get |x-2|. Now putting the values of x in we get: 6, 5, 4 and the graph is also displaced sideways so the solution is the transformed f(x)=|x+3|-5.
