we know that
The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite
so
In this problem
[tex]94\°=\frac{1}{2}[arc\ SR+arc\ TU][/tex]
we have
[tex]arc\ SR=106\°[/tex]
Solve for measure of the arc TU
[tex]188\°=[arc\ SR+arc\ TU][/tex]
[tex]arc\ TU=188\°-106\°[/tex]
[tex]arc\ TU=82\°[/tex]
therefore
the answer is
the measure of the arc TU is [tex]82\°[/tex]
