PLEASE HELP!!

In ΔJKL, solve for x. Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle L measures 27 degrees.

74.89
30.29
38.16
66.73

Respuesta :

The value of x in ΔJKL is 38.16

In the attached photo,

Angle θ = 27°

Adjacent = 34

Hypothenus = x =?

We can obtain the value of x by using the cosine ratio as illustrated below:

Cos θ = Adjacent / Hypothenus

Cos 27 = 34 / x

Cross multiply

xCos 27 = 34

Divide both side by Cos 27

x = 34 / Cos 34

x = 38.16

Therefore, the value of x is 38.16

Learn more about trig ratios on: https://brainly.com/question/22045116

Ver imagen Eduard22sly

Answer:

38.16

Step-by-step explanation:

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