Respuesta :

[tex]2 \sqrt{98} \cdot \sqrt{2} =2 \sqrt{49\times2} \cdot \sqrt{2} \\ \\ =2 \sqrt{49} \cdot \sqrt{2} \cdot \sqrt{2} =2\times7\times2 \\ \\ =28[/tex]

Answer: 28 is the answer.

Explanation: Given expression is [tex]2.\sqrt{98} \sqrt{2}[/tex]

Since, we can write,

⇒ [tex]2.\sqrt{98} \sqrt{2}= 2.\sqrt{49\times 2} \times\sqrt{2}[/tex]

⇒[tex]2.\sqrt{98} \sqrt{2}= 2.\sqrt{49}\times \sqrt{2} \times\sqrt{2}[/tex]

⇒[tex]2.\sqrt{98} \sqrt{2}= 2.\sqrt{49}\times 2[/tex] ( [tex]\sqrt{2} \times \sqrt{2} =2[/tex])

⇒[tex]2.\sqrt{98} \sqrt{2}= 2\times7\times2[/tex] ( Since, [tex]\sqrt{49} =7[/tex])

[tex]2.\sqrt{98} \sqrt{2}= 28[/tex]