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The coordinates of  square ABCD are A(0, 0) , B(a, 0) , C(, a), and  D(0, ).

The slope of AC¯¯¯¯¯ , when simplified, is equal to .

The slope of BD¯¯¯¯¯, when simplified, is equal to −1 .

The product of the slopes is equal to .

Therefore, AC¯¯¯¯¯ is perpendicular to BD¯¯¯¯¯

.Complete the coordinate proof of the theorem.


Enter your answers in the boxesThe coordinates of square ABCD are A0 0 Ba 0 C a and D0 The slope of AC when simplified is equal to The slope of BD when simplifi class=