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The coordinates of square ABCD are A(0, 0) , B(a, 0) , C(, a), and D(0, ).
The slope of AC¯¯¯¯¯ , when simplified, is equal to .
The slope of BD¯¯¯¯¯, when simplified, is equal to −1 .
The product of the slopes is equal to .
Therefore, AC¯¯¯¯¯ is perpendicular to BD¯¯¯¯¯
.Complete the coordinate proof of the theorem.
