The mid-point of line segment AB is (0,2) which is equidistant from the points A(-3,2) and B(3,2). So, (0,2) this part of the coordinate plane will be equidistant from the given points.
Given points are (-3,2) and (3,2). Now, it is required to find the part of the plane which is equidistant from these two points.
The part of the plane will simply be the mid-point of the line segment joining the given points. This is because, the mid-point of such segment will represent equal distance or length from the given points.
Use the section formula, to get the mid-point of line joining (-3,2) and (3,2).
[tex]x=\dfrac{x_1+x_2}{2}\\x=\dfrac{-3+3}{2}\\x=0\\y=\dfrac{y_1+y_2}{2}\\x=\dfrac{2+2}{2}\\x=2\\[/tex]
Therefore, the mid-point is (0,2) which is equidistant from the points A(-3,2) and B(3,2).
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