The word CALCULUS contains
2 C's + 1 A + 2 L's + 2 U's + 1 S = 8 letters, in all.
The number of distinct permutations of all these 8 letters
taken together is
... ( 8! ) / [ (2!) (1!) (2!) (2!) (1!) ]
= [ 8 · (7!) ] / 8
= 7 · (6!)
= 7 ( 720 )
= 5040 ........................................... .