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How many grams of sucrose, C12H22O11, are in a 94.2 mL sample of a 2.6 M sucrose solution?

Respuesta :

get the mass # of each element since its asking for grams 
C- 12.011x12 
H-1.008x22 
O- 15.999x11 
add all of those together to get the mass 
put 2.6 moles on the top - so its the mass x 2.6 then divide by 94.2 Ml 
EjerciciosFyQ
Molar (M) means mol of solute in volume of solution (expressed by liters):

[tex]2.6\frac{mol}{L}\cdot 94.2\cdot 10^{-3}\ L = 0.245\ mol[/tex]

The molecular weight of sucrose is: 12·12 + 22·1 + 11·16 = 342 g/mol.

[tex]0.245\ mol\ C_{12}H_{22}O_{11}\cdot \frac{342\ g}{1\ mol} = \bf 83.79\ g\ C_{12}H_{22}O_{11}[/tex]